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What combination of delta H and delta S values always produces a negative free-energy change?
Best reply by Domi:
ΔG = ΔH – T.ΔS
When ΔS is positive and ΔH is negative, a process is always spontaneous (ΔG < 0).
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What combination of delta H and delta S values always produces a negative free-energy change?
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the equation is ^g=^h-(t^s) i am using the ^ in place of the triangle representing change. so therfore a negative (-)h and a positive (+)s would result in negative g. make sure the temperature is in kelvin