Anyone know how to do a standard free energy reaction problem in chemistry?

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When propanol (CH3CH2CH2OH ) is combusted, such as when in a gasoline blend, the following reaction occurs:
2CH3CH2CH2OH(l) + 9O2 —-> 6CO2(g) + 8H20(g)
Based on the standard free energies of formation given in the table below, what is the standard free energy change for this reaction?
Substance
()
CH3CH2CH2OH(l)360.5
O2(g)0
CO2(g)394.4
H2O(g)228.6

Best reply by Halchemist:

delta G = Gproducts – G reactants
= 6x-394.4 + 8 x -228.6 – (360.5 x 2) = -15200
dellta G/mole = -7500, kJ

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Anyone know how to do a standard free energy reaction problem in chemistry?

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