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When propanol (CH3CH2CH2OH ) is combusted, such as when in a gasoline blend, the following reaction occurs:
2CH3CH2CH2OH(l) + 9O2 —-> 6CO2(g) + 8H20(g)
Based on the standard free energies of formation given in the table below, what is the standard free energy change for this reaction?
Best reply by Halchemist:
delta G = Gproducts – G reactants
= 6x-394.4 + 8 x -228.6 – (360.5 x 2) = -15200
dellta G/mole = -7500, kJ